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[R-meta] Meta-Analysis: Proportion in overall survival rate

Dear Michael, Gerta and List,

I would like to cross-check with you what I have done.

I have restricted myself to Kaplan-Meier studies which gave the number at
risk at 2 years, and also n_0 at baseline.

I then estimated the absolute number of those surviving as *n_t *= n_0*S(t)
following Gerta's idea. I took the reported proportions at 2 years to
represent the S(t).

I calculated the standard error (SE) using the formula: *se *= square root (
*p*(1-*p*)/n). Where *p* = proportion at 2 years i.e. S(t)
, n = *n_t*, the estimated number of of those surviving.

I then used the random effects model in metafor as follows:
rma(yi = *p*, sei = *se*, data=mydata, method="REML")

The resulting estimate seems reasonable to me. But I want to confirm with
you if this is the way one would input SE and the proportion to the
function.

Welcome any comments.

Sincerely,
nelly
On Mon, May 25, 2020 at 9:34 AM ne gic <negic4 at gmail.com> wrote: