-----Original Message-----
From: Diego Grados Bedoya [mailto:diegogradosb at gmail.com]
Sent: Thursday, 29 April, 2021 9:03
To: Viechtbauer, Wolfgang (SP)
Cc: R meta
Subject: Re: [R-meta] converting effect sizes from RR to lnRR without original
data
Dear?Wolfgang,
Thank you for your answer. There is a mistake in the online version of the article
(https://doi.org/10.1126/sciadv.aba1715). The suggested equation is:
lnRR = ln(RR) -?n * SE^2 / (2 * RR^2)
Greetings,
Diego
On Wed, 28 Apr 2021 at 12:11, Viechtbauer, Wolfgang (SP)
<wolfgang.viechtbauer at maastrichtuniversity.nl> wrote:
Dear Diego,
If I need to convert an RR to lnRR, I just take the log. I don't know what that
equation is supposed to do. It might help if you would tell you where you got it
from.
Best,
Wolfgang
-----Original Message-----
From: R-sig-meta-analysis [mailto:r-sig-meta-analysis-bounces at r-project.org] On
Behalf Of Diego Grados Bedoya
Sent: Wednesday, 28 April, 2021 10:52
To: R meta
Subject: [R-meta] converting effect sizes from RR to lnRR without original data
Dear all,
I would like to convert an effect size from RR to lnRR. I do not have
access to the original data. I just have the effect size (RR), standard
error (SE) and the number of comparisons (N). I read that a direct log
transformation of an RR can lead to an overestimation of the effect size,
thus the authors proposed a correction for the log transformation as
lnRR = ln(RR) - NSE2 x (2 RR2) - 1
However, the formula is not fully described and there is not no further
reference. I was trying to make sense of it but can not get good results. I
wonder if you have some references or thoughts about it?
Thank you in advance,
Greetings,
Diego