Hi all, I have two questions. 1) In this article <https://mail.jjay.cuny.edu/owa/redir.aspx?C=jnnID1xyBS33HM9BECtjC_Z23ilF54mDEf0zdCS88qMPhZkvMsXUCA..&URL=http%3a%2f%2fwww.metafor-project.org%2fdoku.php%2fanalyses%3amiller1978>, Dr. Wolfgang Viechtbauer used the harmonic mean of the sample sizes to back-transform the estimated average transformed proportion (the pooled proportion). If I don't want to use the harmonic mean, is it possible to use the *transf.ipft*, instead of the *transf**=**transf.ipft.hm <http://transf.ipft.hm>*, to get the pooled proportion? If so, how do I do that? 2) One of the reasons I asked the question is due to this article: Meta-analysis of prevalence <https://drive.google.com/open?id=0B41wTxciaMqtNXVSNEFGazdPWFU>. The authors of this article developed an Exel-based meta-analysis add-in (MetaXL). MetaXL uses a different method to perform the double arcsine transformation. The differences are two-fold. First, MetaXL uses a different definition of the Freeman-Tukey transformation. The PFT values (yi) are twice as large as the values computed by metafor and the variances (vi) are four times as large. The different definitions are also explained here <http://www.metafor-project.org/doku.php/faq#how_is_the_freeman-tukey_trans> . Second, it does not use the harmonic mean to perform the back-transformation. According to the authors, it is better not to use the harmonic mean because their simulation studies suggest that the harmonic mean is not stable. Basically, I'm asking how to get metafor to get the same results as obtained in MetaXL? Do you agree with the MetaXL authors that it is better not to use the harmonic mean? I hope my questions make sense. Feel free to ask me anything if you don't understand. P.S. Dowload MetaXL here: http://www.epigear.com/index_files/metaxl.html P.S.S. After you install MetaXL, open example "SchizophreniaPrev" to get a sense of how it performs meta-analysis of proportions. Cheers, Naike
[R-meta] Freeman-Tukey double arcsine transformation and harmonic mean
3 messages · Naike Wang, Viechtbauer Wolfgang (STAT)
Hi Naike, The first linked got mangled up. It is: http://www.metafor-project.org/doku.php/analyses:miller1978 The exact back/inverse transformation of the Freeman-Tukey (double arcsine) transformation requires that we specify the sample size for the transformed value. So: library(metafor) dat <- escalc(measure="PFT", xi=4, ni=10)
dat
yi vi 1 0.6936 0.0238 transf.ipft(dat$yi, ni=10) yields a proportion of 0.4 as expected. Now if you synthesize a whole bunch of transformed values and you want to back-transform that value to a proportion, you still need to specify some value for the sample size if you want to use the exact back-transformation. Miller (1978), who derived the back-transformation, suggested to use the harmonic mean of the sample sizes. That is what transf.ipft.hm() does. Using the harmonic mean of the sample sizes is a rather heuristic method that may or may not work so well. I would be interested in any published papers that show this to be a problem. I don't know what MetaXL does for the back-transformation, but maybe it just pretends that the values are arcsine-square-root transformed proportions and then uses the back-transformation for that -- which does not require one to specify the sample size. The difference is typically negligible: transf.iarcsin(dat$yi) yields 0.4086998. But then, one might as well just do the meta-analysis directly with the AS transformed proportions: dat <- escalc(measure="PAS", xi=4, ni=10) dat
dat
yi vi 1 0.6847 0.0250 transf.iarcsin(dat$yi) gives back 0.4 exactly. Or one could go directly to a logistic mixed-effects model for the analysis. You can do that with rma.glmm(). Best, Wolfgang
Wolfgang Viechtbauer, Ph.D., Statistician | Department of Psychiatry and Neuropsychology | Maastricht University | P.O. Box 616 (VIJV1) | 6200 MD Maastricht, The Netherlands | +31 (43) 388-4170 | http://www.wvbauer.com >-----Original Message----- >From: R-sig-meta-analysis [mailto:r-sig-meta-analysis-bounces at r- >project.org] On Behalf Of Naike Wang >Sent: Friday, July 07, 2017 15:25 >To: r-sig-meta-analysis at r-project.org >Subject: [R-meta] Freeman-Tukey double arcsine transformation and harmonic >mean > >Hi all, >I have two questions. >1) In this article ><https://mail.jjay.cuny.edu/owa/redir.aspx?C=jnnID1xyBS33HM9BECtjC_Z23ilF5 >4mDEf0zdCS88qMPhZkvMsXUCA..&URL=http%3a%2f%2fwww.metafor- >project.org%2fdoku.php%2fanalyses%3amiller1978>, >Dr. Wolfgang Viechtbauer used the harmonic mean of the sample sizes to >back-transform the estimated average transformed proportion (the pooled >proportion). If I don't want to use the harmonic mean, is it possible to >use the *transf.ipft*, instead of the *transf**=**transf.ipft.hm ><http://transf.ipft.hm>*, to get the pooled proportion? If so, how do I do >that? > >2) One of the reasons I asked the question is due to this article: >Meta-analysis >of prevalence ><https://drive.google.com/open?id=0B41wTxciaMqtNXVSNEFGazdPWFU>. The >authors of this article developed an Exel-based meta-analysis add-in >(MetaXL). MetaXL uses a different method to perform the double arcsine >transformation. The differences are two-fold. >First, MetaXL uses a different definition of the Freeman-Tukey >transformation. The PFT values (yi) are twice as large as the values >computed by metafor and the variances (vi) are four times as large. The >different definitions are also explained here ><http://www.metafor-project.org/doku.php/faq#how_is_the_freeman- >tukey_trans> >. >Second, it does not use the harmonic mean to perform the >back-transformation. According to the authors, it is better not to use the >harmonic mean because their simulation studies suggest that the harmonic >mean is not stable. >Basically, I'm asking how to get metafor to get the same results as >obtained in MetaXL? Do you agree with the MetaXL authors that it is better >not to use the harmonic mean? > >I hope my questions make sense. Feel free to ask me anything if you don't >understand. > >P.S. Dowload MetaXL here: http://www.epigear.com/index_files/metaxl.html >P.S.S. After you install MetaXL, open example "SchizophreniaPrev" to get a >sense of how it performs meta-analysis of proportions. > >Cheers, >Naike
Thank you for your answer, Dr. Viechtbauer.
I think you were right. MetaXL seems to apply the inverse transformation of
the arcsine transformation to double arcsine transformed proportions in
order to pool an average proportion. I tested this assumption with
the example dataset "SchizophreniaPrev" built in MetaXL and yielded very
similar results.
Here's my code:
dat=read.csv("your working directory\\schizophreniaprev.c
sv",header=T,sep=",")
transf.ies=escalc(measure="PFT",xi=cases,ni=total,data=dat, add=0) #computing
individual transformed proportions using the double arcsine transformation
transf.pes=rma(yi,vi,data=transf.ies,method="DL",weighted=TRUE) #pooling
transformed proportions under the random effect size model
pes=predict(transf.pes,transf=transf.iarcsin) #back-transforming
with inverse of the arcsine transformation
print(pes,digits=4)
My results:
pred ci.lb ci.ub 0.5856 0.5089 0.6603
MetaXL results:
pred ci.lb ci.ub 0.5875 0.5098 0.6632 Thank you again for your time. Cheers, Naike 2017-07-07 9:41 GMT-04:00 Viechtbauer Wolfgang (SP) < wolfgang.viechtbauer at maastrichtuniversity.nl>:
Hi Naike, The first linked got mangled up. It is: http://www.metafor-project. org/doku.php/analyses:miller1978 The exact back/inverse transformation of the Freeman-Tukey (double arcsine) transformation requires that we specify the sample size for the transformed value. So: library(metafor) dat <- escalc(measure="PFT", xi=4, ni=10)
dat
yi vi 1 0.6936 0.0238 transf.ipft(dat$yi, ni=10) yields a proportion of 0.4 as expected. Now if you synthesize a whole bunch of transformed values and you want to back-transform that value to a proportion, you still need to specify some value for the sample size if you want to use the exact back-transformation. Miller (1978), who derived the back-transformation, suggested to use the harmonic mean of the sample sizes. That is what transf.ipft.hm() does. Using the harmonic mean of the sample sizes is a rather heuristic method that may or may not work so well. I would be interested in any published papers that show this to be a problem. I don't know what MetaXL does for the back-transformation, but maybe it just pretends that the values are arcsine-square-root transformed proportions and then uses the back-transformation for that -- which does not require one to specify the sample size. The difference is typically negligible: transf.iarcsin(dat$yi) yields 0.4086998. But then, one might as well just do the meta-analysis directly with the AS transformed proportions: dat <- escalc(measure="PAS", xi=4, ni=10) dat
dat
yi vi 1 0.6847 0.0250 transf.iarcsin(dat$yi) gives back 0.4 exactly. Or one could go directly to a logistic mixed-effects model for the analysis. You can do that with rma.glmm(). Best, Wolfgang -- Wolfgang Viechtbauer, Ph.D., Statistician | Department of Psychiatry and Neuropsychology | Maastricht University | P.O. Box 616 (VIJV1) | 6200 MD Maastricht, The Netherlands | +31 (43) 388-4170 | http://www.wvbauer.com
-----Original Message----- From: R-sig-meta-analysis [mailto:r-sig-meta-analysis-bounces at r- project.org] On Behalf Of Naike Wang Sent: Friday, July 07, 2017 15:25 To: r-sig-meta-analysis at r-project.org Subject: [R-meta] Freeman-Tukey double arcsine transformation and harmonic mean Hi all, I have two questions. 1) In this article <https://mail.jjay.cuny.edu/owa/redir.aspx?C=
jnnID1xyBS33HM9BECtjC_Z23ilF5
4mDEf0zdCS88qMPhZkvMsXUCA..&URL=http%3a%2f%2fwww.metafor- project.org%2fdoku.php%2fanalyses%3amiller1978>, Dr. Wolfgang Viechtbauer used the harmonic mean of the sample sizes to back-transform the estimated average transformed proportion (the pooled proportion). If I don't want to use the harmonic mean, is it possible to use the *transf.ipft*, instead of the *transf**=**transf.ipft.hm <http://transf.ipft.hm>*, to get the pooled proportion? If so, how do I
do
that? 2) One of the reasons I asked the question is due to this article: Meta-analysis of prevalence <https://drive.google.com/open?id=0B41wTxciaMqtNXVSNEFGazdPWFU>. The authors of this article developed an Exel-based meta-analysis add-in (MetaXL). MetaXL uses a different method to perform the double arcsine transformation. The differences are two-fold. First, MetaXL uses a different definition of the Freeman-Tukey transformation. The PFT values (yi) are twice as large as the values computed by metafor and the variances (vi) are four times as large. The different definitions are also explained here <http://www.metafor-project.org/doku.php/faq#how_is_the_freeman- tukey_trans> . Second, it does not use the harmonic mean to perform the back-transformation. According to the authors, it is better not to use the harmonic mean because their simulation studies suggest that the harmonic mean is not stable. Basically, I'm asking how to get metafor to get the same results as obtained in MetaXL? Do you agree with the MetaXL authors that it is better not to use the harmonic mean? I hope my questions make sense. Feel free to ask me anything if you don't understand. P.S. Dowload MetaXL here: http://www.epigear.com/index_files/metaxl.html P.S.S. After you install MetaXL, open example "SchizophreniaPrev" to get a sense of how it performs meta-analysis of proportions. Cheers, Naike
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