Thanks, I was aware of that for categorical and some of the other
families but thought I could get away with it here and I wasn't
quite sure otherwise how to calculate the relevant ratio (thanks for
providing that too).
With smaller sample sizes repeatability still seems to get
misestimated and stuck close to zero even with long runs but running
multiple chains seem to resolve that.
Thanks again,
Ned
On 10/21/2014 3:05 PM, Jarrod Hadfield wrote:
Hi,
The residual variance of a binary response cannot be estimated, so use
prior1 = list(R = list(V = 1, fix=1),
G = list(G1 = list(V = 1, nu = 0.002)))
In this example it is more efficient to aggregate success/failures
of an individual into a multi-trial binomial response and use:
prior2 = list(R = list(V = 1, nu=0.002))
sim.mcmc2<-MCMCglmm(cbind(Fail,Success)~1,
family="multinomial2", prior=prior2,
nitt = 260000, thin = 200, burnin = 60000,
verbose=FALSE,data=ind.data)
sim.mcmc2$VCV/(sim.mcmc2$VCV+pi^2/3)
Cheers,
Jarrod