I think the equivalent to fm1 is actually fm2<-lmer(log(y)~1+x+(-1+x|group), na.action="na.omit", data=...)
On 03/28/12, Ista Zahn wrote:
Hi Antoine, I think you want fm2<-lmer(log(y)~-1+x+(-1+x|group), na.action="na.omit", data=...) no? Best, Ista 2012/3/28 Antoine TARDIF <antoine.tardif at usherbrooke.ca>:
Dear all, I would like to fit a multilevel linear model, with varying slope but with intercepts fixed at zero (in my experiment, all the samples have the same value at time=0). I have both nested and non-nested factors, but in a first step, we would like to fit a lmer model "fm2" equivalent to this lme model "fm1" : library(nlme) fm1<-lme(log(y)~x, random=~-1+x|group, na.action="na.omit", data=...) I tried this code for the lmer function : library(lme4) fm2<-lmer(log(y)~-1+x+(-1+y|group), na.action="na.omit", data=...) 1. Instead of providing similar results to fm1, fm2 results do not make sense. Is there a mistake in the structure of the fm2 code ? 2. I also have an other question : ?> coef(fm1) works, but ?> coef(fm2) shows this error message : "unable to align random and fixed effects" What does it mean ? If someone could help me, thanks a lot in advance.. Antoine Tardif -- ? ? ?Antoine TARDIF ? D?partement de Biologie ? Universit? de Sherbrooke ? Sherbrooke (Qc) ? J1K 2R1 Canada ? Bureau D5-0204 ? (+ 1) 819 821 8000 poste 61928 ? antoine.tardif at usherbrooke.ca ? ? ? ?[[alternative HTML version deleted]]
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