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On 11-06-19 07:35 AM, Reinhold Kliegl wrote:
I also did a quick scan of the paper. Here is a quote from page 156:
"In richly parameterised models, such as those containing random
effects, estimating the number of degrees of freedom (or alternatively
the number of ?effective? parameters) is neither straightforward nor
necessarily unambiguous (Hodges & Sargent 2001). Hence, attention here
is restricted to models that contain fixed effects only."
I suspect this puts us back to square 1. Or is there evidence in the
paper to the contrary?
Reinhold Kliegl
I'm a bit confused by this statement since I don't see what one needs
the degrees of freedom for in the parametric bootstrap/simulated null
distribution case ... they do some comparisons with simpler asymptotic
approaches (AIC, Vuong's test, etc.) that would require knowing (at
least differences among models in) degrees of freedom. Maybe they just
wanted to keep the paper short?
Ben Bolker
On Fri, Jun 17, 2011 at 11:47 PM, Ben Bolker <bbolker at gmail.com> wrote:
Based on a very quick glance at the paper, I suspect that the
parametric bootstrap approach illustrated in recent releases of the lme4
package (library("lme4"); help("simulate-mer")) should be easily
adaptable (if my guess is correct and what they are doing is evaluating
deviance of model B based on simulations conditional on model A fits and
vice versa?)
Ben Bolker
On 11-06-18 01:44 PM, Arnaud Mosnier wrote:
Thanks for this reference, I will try to find this paper.
I would also be interested by any comments from the statistics masters
that we can find on this list.
If it's correct ... is there any package (function) allowing to apply
their suggested approach ("simulation-based approach").
Arnaud
2011/6/17 luca borger <luca.borger at cebc.cnrs.fr>:
Thanks to remind me that LRT are only for nested model
actually, Lewis et al. (2011, Abstract below) just published a paper where they claim that LRTs can be used also for non nested models ("This fact is well-established in the statistical literature, but not widely used in ecological studies."). Has anyone read this paper? I'd be interested to hear any comments (incl. if you believe the authors' approach could be used also for GLMMs).
Cheers,
Luca
http://onlinelibrary.wiley.com/doi/10.1111/j.2041-210X.2010.00063.x/abstract
A unified approach to model selection using the likelihood ratio test
Fraser Lewis, Adam Butler, Lucy Gilbert
Methods in Ecology and Evolution
Volume 2, Issue 2, pages 155162, April 2011
DOI: 10.1111/j.2041-210X.2010.00063.x
Summary
1.Ecological count data typically exhibit complexities such as overdispersion and zero-inflation, and are often weakly associated with a relatively large number of correlated covariates. The use of an appropriate statistical model for inference is therefore essential. A common selection criteria for choosing between nested models is the likelihood ratio test (LRT). Widely used alternatives to the LRT are based on information-theoretic metrics such as the Akaike Information Criterion.
2.It is widely believed that the LRT can only be used to compare the performance of nested models i.e. in situations where one model is a special case of another. There are many situations in which it is important to compare non-nested models, so, if true, this would be a substantial drawback of using LRTs for model comparison. In reality, however, it is actually possible to use the LRT for comparing both nested and non-nested models. This fact is well-established in the statistical literature, but not widely used in ecological studies.
3.The main obstacle to the use of the LRT with non-nested models has, until relatively recently, been the fact that it is difficult to explicitly write down a formula for the distribution of the LRT statistic under the null hypothesis that one of the models is true. With modern computing power it is possible to overcome this difficulty by using a simulation-based approach.
4.To demonstrate the practical application of the LRT to both nested and non-nested model comparisons, a case study involving data on questing tick (Ixodes ricinus) abundance is presented. These data contain complexities typical in ecological analyses, such as zero-inflation and overdispersion, for which comparison between models of differing structure e.g. non-nested models is of particular importance.
5.Choosing between competing statistical models is an essential part of any applied ecological analysis. The LRT is a standard statistical test for comparing nested models. By use of simulation the LRT can also be used in an analogous fashion to compare non-nested models, thereby providing a unified approach for model comparison within the null hypothesis testing paradigm. A simple practical guide is provided in how to apply this approach to the key models required in the analyses of count data.
-----Original Message-----
From: Arnaud Mosnier <a.mosnier at gmail.com>
To: Andrew Miles <rstuff.miles at gmail.com>
Date: Fri, 17 Jun 2011 12:44:50 -0400
Subject: Re: [R-sig-ME] Model selection, LRT test
Andrew,
Thanks to remind me that LRT are only for nested model ... this is not
the case in my situation.
Arnaud
2011/6/17 Andrew Miles <rstuff.miles at gmail.com>:
What types of models are you running?
There may be two issues at play.
1. Likelihood ratio tests are only for nested models (i.e. models where the
variables in one model are a subset of the variables in the other) so by
definition there will always be a difference in degrees of freedom.
2. With mixed models you can only use a likelihood ratio test when the model
returns a deviance score - so not for generalized linear mixed models in
most cases (though I believe that you can use LRT's if they are estimated
using a type of numerical integration, but not any sort of quasi-likelihood
like PQL)
Andrew
On Fri, Jun 17, 2011 at 11:12 AM, Arnaud Mosnier <a.mosnier at gmail.com>
wrote:
Dear list,
If I do not make a mistake, use of Likelihood ratio test is precluded
when two models have the same number of degree of freedom.
Is there a way to test which one is the best when both are close in
AIC value (difference < 5) or do I have to conclude that they are
"equivalent" ?
Thanks
Arnaud