Graph Two Series over Time

Dear Randall:

I could not find package 9or function) called "*tidyr*". I install all
other packages, but could not find tidyr.

with many thanks
steve

On Tue, Dec 29, 2015 at 5:43 PM, Randall Pruim <rpruim at calvin.edu> wrote:

A few more suggestions and an update to my ggplot2 plot.

  1) I recommend using SPACES in your code to make things more readable.
  2) Coding things with COLOR isn?t really very useful.  This is an
additional variable and should be coded as such.
  3) I don?t really know what detected means, but I?ve coded it as a
logical variable.  You could use a factor or character vector instead.
  4) You have used inconsistent date formatting which (without my edits)
will cause some years to be 0005 and others to be 2005.  (This will be
immediately clear when the plot spans 2000 years ? that?s how I detected
the problem.)

Here?s what my first draft would look like:


### Put data into a data frame -- avoid loose vectors
library(dplyr); library(lubridate); require(tidyr)
library(ggplot2)

# recreate your data in a data frame
MyData <- data_frame(
  Well1 =
c(0.005,0.005,0.004,0.006,0.004,0.009,0.017,0.045,0.05,0.07,0.12,0.10,NA,0.20,0.25),
  Well2 =
c(0.10,0.12,0.125,0.107,0.099,0.11,0.13,0.109,NA,0.10,0.115,0.14,0.17,NA,0.11),
  dateString =
c("2Jan05","7April05","17July05","24Oct05","7Jan06","30March06","28Jun06",

 "2Oct06","17Oct06","15Jan07","10April07","9July07","5Oct07","29Oct07","30Dec07"),
  date = dmy(dateString)
)

# put the data into "long" format
MyData2 <-
  MyData %>%
  gather(location, concentration, Well1, Well2) %>%
  mutate(detected = TRUE)

# hand-code your colored values (should be double checked for accuracy)

MyData2$detected[c(1, 2, 5, 15 + 1, 15 + 5, 15 + 10)] <- FALSE

# Create plot using ggplot2

ggplot( data = MyData2 %>% filter(!is.na(concentration)),
        aes(x = date, y = concentration, colour = location)) +
  geom_line(alpha = 0.8) +
  geom_point( aes(shape = detected, group = location), size = 3, alpha =
0.8) +
  scale_shape_manual(values = c(1, 16)) +
  theme_minimal()

On Dec 26, 2015, at 6:02 AM, Steven Stoline <sstoline at gmail.com> wrote:

Dear Randall:


Thank you very much for the details and for your support and patience.



### This how are the original data look like:
### ---------------------------------------------------

Well1<-c(0.005,0.005,0.004,0.006,0.004,0.009,0.017,0.045,0.05,0.07,0.12,0.10,NA,0.20,0.25)

Well2<-c(0.10,0.12,0.125,0.107,0.099,0.11,0.13,0.109,NA,0.10,0.115,0.14,0.17,NA,0.11)

date<-c("2Jan2005","7April05","17July05","24Oct05","7Jan06","30March06","28Jun06","2Oct06","17Oct06","15Jan07","10April07","9July07","5Oct07","29Oct07","30Dec07")

The data values in red font are Non-detected. So I need to make

difference between these non-detected values and the detected ones in the
graph.

For example, solid circle for the detected ones, and open circles for

the non-detected one (the ones in red font).

So, I was trying to use pch for.



Please notice that, now, both data sets Well1 and Well2, and date have

the same length of 15, but Well1 has one NA, and Well2 has two NA.

Happy Holiday and Happy Christmas (if you are celebrating)

with many thanks
steve

On Thu, Dec 24, 2015 at 9:31 AM, Randall Pruim <rpruim at calvin.edu>

wrote:

Steve,

This is on the edge of what R-sig-teaching is for (since it isn?t really

about teaching).  But since I think there are elements of what you are
doing that lead students to think that R is terrible, I?ll show you how I
might approach things.

First a few comments about my solution.

1) I generally avoid loose vectors.  I prefer to use data frames to keep

related vectors related.

2) I prefer to code dates as dates.  I would be very nervous about code

that manually sets the axis labels differently from the data.  That can
lead to all sorts of bad errors down the road if you change the data and
forget to change the labels and often indicates you don?t have the data
formatted the way you should.  (Note:  I added day of month values to your
dates that had none.)  The lubridate package makes it easy to create dates
from strings.

3) I rarely use base graphics, so I?ll show you solutions using lattice

and ggplot2.  There may be nice ways to do this in base graphics as well.

4) I?m ignoring the color choices, title, etc.  All that can be easily

added, but I?m focusing on getting the data display correct.  That?s
generally the approach I take to plotting:  First get the data display
correct, then fancy up titles, colors, fonts, etc.  It?s saves lots of
times, because often once I see the plot, I realize it isn?t what I need,
so there is no reason to gussy it up.

5) I prefer (and lattice and ggplot2) encourage keeping the data

manipulation in one location and the plotting after that rather than going
back and forth between those two types of operations.  I find that it makes
the code easier to read.

6) One of your series as fewer points than the other.  I made the

assumption that the missing value was at the end.  That should be changed
to whatever is correct for your data.

7) I don?t know what you were using pch to indicate, so I created a

variable called ?group? with values 0 and 15.  The variable and its values
should ideally be renamed to reflect what they represent.  That will make
your code easier to read and produce better labeling of the plot.

And one note about your code.

6*0:max_y

probably doesn?t do what you expect since the 6 does nothing here

(because 6 * 0 = 0).  You could do 6 * (0:max_y), but isn?t clear why you
would want the range of the plot to be six times that of the data.  Maybe
you were thinking something like seq(0, max_y, length.out = 6), but that
will give pretty ugly breakpoints.  In any case, the plots below do a fine
job of setting the axes by default, and each system allows you to tune them
if you disagree with the default for a particular plot.

With that much preamble, the code is now shorter than the introduction.


### Put data into a data frame -- avoid loose vectors
library(dplyr); library(lubridate)

# if i knew what you were using pch for, i would name group and its

values to match

MyData <- data_frame(
  Well1 =

c(0.005,0.005,0.004,0.006,0.004,0.009,0.017,0.045,0.05,0.07,0.12,0.10,0.20,0.25),

  Well2 =

c(0.10,0.12,0.125,0.107,0.099,0.11,0.13,0.109,0.10,0.115,0.14,0.17,0.11,NA),

  dateString =

c("1Jan05","1April05","1Jul05","1Oct05","1Jan06","1March06","1Jun06","2Oct06","17Oct06","1Jan07","1April07","1Jul07","1Oct07","1Dec07"),

  date = dmy(dateString),
  group = factor(c(0,0,15,15,0,15,15,15,15,15,15,15,15,15))
)

## using lattice
## lattice makes plotting two series easy
## but doesn't make it as easy to have different symbols along the same

series

library(lattice)
xyplot(Well1 + Well2 ~ date, data = MyData, type = c("p","l"), auto.key

= TRUE)

## better legend
xyplot(Well1 + Well2 ~ date, data = MyData, type = c("p","l"),
       auto.key = list(points = TRUE, lines = TRUE))

## using ggplot2
## for highly customized plots, i generally find ggplot2 works better
## i would reshape the data with tidyr before plotting (could be don in

lattice as well)

library(ggplot2); library(tidyr)

MyData2 <-
  MyData %>%
  gather(location, concentration, Well1, Well2)

ggplot( data = MyData2, aes(x = date, y = concentration, colour =

location)) +

  geom_line() +
  geom_point( aes(shape = group), size = 2)

xyplot(concentration ~ date, data = MyData2, groups = location, type =

c("p", "l"),

       auto.key = TRUE)

## without reshaping, you can plot 4 layers well manually, but the

default labeling isn?t as nice

ggplot(data = MyData) +
  geom_line(aes(x = date, y = Well1, colour = "Well1")) +
  geom_line(aes(x = date, y = Well2, colour = "Well2")) +
  geom_point(aes(x = date, y = Well1, colour = "Well1", shape = group)) +
  geom_point(aes(x = date, y = Well2, colour = "Well2", shape = group))


Happy Holidays.  I hope one of these approaches will get you headed in

the right direction.

?rjp

On Dec 24, 2015, at 7:51 AM, Steven Stoline <sstoline at gmail.com> wrote:

Dear All:

I am trying to plot two series in one graph. But I have some

difficulties

to set up the y-axis lim. Also, the second series is not correctly

graphed.

*Here is what I tried to do:*


### Define 2 vectors

Well1<-c(0.005,0.005,0.004,0.006,0.004,0.009,0.017,0.045,0.05,0.07,0.12,0.10,0.20,0.25)

Well2<-c(0.10,0.12,0.125,0.107,0.099,0.11,0.13,0.109,0.10,0.115,0.14,0.17,0.11)

### Calculate range from 0 to max value of Well1 and Well2
### g_range <- range(0, Well1, Well2)

max_y <- max(Well1, Well2)

### Graph Groundwater Concentrations using y axis that ranges from 0 to

max

### value in Well1 or Well2 vector.  Turn off axes and
### annotations (axis labels) so we can specify them yourself

plot(Well1, type="o", pch=c(0,0,15,15,0,15,15,15,15,15,15,15,15,15),
col="blue", ylim=c(0,max_y), axes=FALSE, ann=FALSE, , lwd=3, cex=1.25)

###

axes=FALSE,

### Make x axis using Jan 2005 - Dec 2008 labels

axis(1, at=1:14,

lab=c("Jan05","April05","Jul05","Oct05","Jan06","March06","Jun06","2Oct06","17Oct06","Jan07","April07","Jul07","Oct07","Dec07"))

*### Make y axis with horizontal labels , Here what I have the major
problem*

### I want the y-axis looks like: 0, 0.05, 0.10, 0.15, 20, 0.25

axis(2, las=0, at=6*0:max_y)  ### max_y


### Create box around plot

box()

### Graph Well2 with red dashed line and square points

### lines(Well2, type="o", pch=22, lty=2, col="red", lwd=3, cex=1.0)

lines(Well2, type="o", pch=c(0,15,15,15,0,15,15,15,0,15,15,15,15),

lty=2,

col="red", lwd=3, cex=1.25)

### Create a title with a red, bold/italic font

title(main="Trichloroethene mg/L from Wells 1 and 2 - 2005-2007",
col.main="red", font.main=2)

### Label the x and y axes with dark green text

title(xlab="Time Points", col.lab=rgb(0,0.5,0))


title(ylab="Trichloroethene mg/L", col.lab=rgb(0,0.5,0))

### Create a legend

legend(1, g_range[2], c("Well1","Well2"), cex=1.0, col=c("blue","red"),
pch=15:15, lty=1:2);




with thanks
steve
-------------------------
Steven M. Stoline
1123 Forest Avenue
Portland, ME 04112
sstoline at gmail.com

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Steven M. Stoline
1123 Forest Avenue
Portland, ME 04112
sstoline at gmail.com

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Steven M. Stoline
1123 Forest Avenue
Portland, ME 04112
sstoline at gmail.com

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