[Rcpp-devel] Copying a NumericVector from a list within a list
On Sat, Apr 12, 2014 at 11:06 PM, Dirk Eddelbuettel <edd at debian.org> wrote:
What can work as a single expression in R sometimes needs to be disentangled at the C++ level to help the compiler find its way through all the templates.
[snip]
// [[Rcpp::export]]
NumericVector fromList(List outer, std::string name) {
List inner = outer[0]; // 0-based offsets in C++
return inner["p"];
}
I've noticed (I think...) having to do this sort of thing, but I want
to ask a question to clarify: is it possible to have the above code
work, but if you instead try:
NumericVector fromList(List outer, std::string name) {
(outer[0])["p"]
}
/*** R x <- c(0.2855202, 0.6731716, 0.8497825, 0.7445254, 0.2382722) innL <- list(p=x) outL <- list(List1=innL) fromList(outL, "p") */ -- Dirk Eddelbuettel | edd at debian.org | http://dirk.eddelbuettel.com
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Krzysztof Sakrejda Organismic and Evolutionary Biology University of Massachusetts, Amherst 319 Morrill Science Center South 611 N. Pleasant Street Amherst, MA 01003 work #: 413-325-6555 email: sakrejda at cns.umass.edu -----------------------------------------------