Search Archives

Hi Patrizio, maybe there is a more efficient way, but you can loop over rows and columns like this ab.recon <- data.frame() ddd.rownames <- rownames(ddd) ddd.colnames <- colnames(ddd) for(cur.row in ddd.rownames){ for(cur.col...

Hi, I think droplevels(df) is what you are looking for. Best wishes, Ulrik On Tue, 1 Mar 2016 at 17:33 hoda rahmati via R-help <r-help at r-project.org> wrote: > Hi all,I have the following...

You could also use kable from the Knitr package Best, Ulrik On Fri, 26 Feb 2016 at 11:17 Uwe Ligges <ligges at statistik.tu-dortmund.de> wrote: > writeLines(paste(do.call(paste, c(liste, sep=" & ")), "\\\\\\hline"), > con = "empf.csv...

Milan, I am not closing the dialog, but without the dialog in the search space, I cannot properly refer to it any more using e.g. the Rcmdr function errorCondition. It has been a long time ago that I wrote...

Dear R package authors, I am currently struggling with differences in test results between R versions 3.5.3 and 3.6.0: There are expected ones (from the new behavior of sample(), which can be switched off by RNGkind...

>Roberto Furlan wrote: > >Hi, >i need to create a fractional factorial design sufficient to estimate the >main effects. >The factors may have any number of levels, let's say any number from 2 to 6. >I've tried to use...

Hi Shivi, I usually do merge.salaries$name <- paste(merge.salaries$nameFirst, merge.salaries$nameLast) also if merge.salaries[, name:=paste("nameFirst","nameLast")] would work, you would end up with a column full of "nameFirst nameLast". Best, Ulrik On Thu...

Hi Yung-Chih, This works for me: library(Vennerable) data("StemCell") venn_res <- Venn(StemCell[1:3]) plot(venn_res, doWeights = TRUE) HTH Ulrik On Thu, 22 Dec 2016 at 20:54 Yung-Chih Lai <yungchihlai at gmail.com> wrote...

I realize now that the dynamic help is no longer implemented via chm apparently. But nevertheless, the intention is certainly to be able to call help WITH links from within R? What can I do to make that work instead...

Also, it will be easier to provide helpful information if you'd describe what in your data you want to compare and what you hope to get out of the comparison. Best wishes, Ulrik Eric Berger <ericjberger at gmail.com...

What is your version of readxl? In my version 1.0, there is no directory called estdata, but there is one called extdata. However, in that directory there is no file called "results.xlsx" Either it was there once and...

I am a huge fan of pheatmap and use it for all my heatmaps. Alternatively you can use ggplot2 and geom_tile Hth Ulrik Jim Lemon <drjimlemon at gmail.com> schrieb am So., 18. Sep. 2016 01:35: > Hi Michael...

I asked the moderators about it. This is the reply "Other moderators have looked into this a bit and may be able to shed more light on it. This is a "new" tactic where the spammers appear to reply to...

Hi Georg, Your for loop iterates over just one value, to get it to work as you intend use for(item in 1:length(kpis)){} HTH Ulrik On Thu, 17 Nov 2016 at 12:18 <G.Maubach at weinwolf.de...

Hi Sema, read.csv2 use ',' as the decimal separator. Since '.' is used in your file, everything becomes a character which in turn makes pam complain that what you pass to the function isn't numeric. Use read.csv2("data.csv...

Hi Val, Take a kook at read.table. If for some reason the file dosen't have the same separator between the columns you can use strsplit after loading the file. This might helpyou along getting data into R: http...

Dear R-sig-Geos, I am quite new to geographical data in R and also to shape files etc., and I have encountered the following difficulty: After reading a publicly available shape file on recent EU elections in Berlin (link...

Hi Elahe, if you look at your subdf, you will see that the column Country - which is not numeric - is still present. You might have other non-number columns, but this I cannot tell. scale expects a numeric matrix. You...

Hi Pedro, I see you use dplyr and ggplot2. Are you looking for something like this: ``` library(ggplot2) library(dplyr) test_data <- data.frame( year = c(rep("2018", 10), rep("2019", 8), rep("2020", 6)), value = sample(c(1:100...

Hi Terry, you can use type.convert instead of as.numeric for numbers with decimals: type.convert(levels(factor(1:6/2)), dec=unlist(options("OutDec"))) Best, Ulrike Am 16.03.2013 12:00, schrieb r-devel-request at r...