Search Archives

Is there any way to use expression() in legend labels with ggplot2? It seems that things like > scale_shape_manual(value = c( > x = expression(italic(x)), > y = expression(italic(y)) > )) don't work. Thanks very much :) -- Using GPG/PGP? Please...

As the title says, I want to apply a function (which itself returns a function) to a list (or vector), and get a list (or vector) of generated functions as the return value, but get unexpected result. Anyone with an...

Hmm, that's my fault when composing this mail, but the problem was really encountered at that time. Nevertheless, neither can I reproduce the problem now, perhaps I just made another mistake at that time. Thanks all the same, and...

Thanks, I'll post to that list if the encountered problem is just about ggplot2. And from the date of the issue on GitHub it seems that I might need to manually work around the problem some more times :) On...

Hello list, is there any R function for generating spline for implicit functions, for example a spline for an two-column data frame where for one value for one variable there maybe several correspondent values for another? Many thanks. Currently...

Thank you very much, though I still don't quite undertdand the explanation :) Nevertheless, I just found a seemingly simple (at least quiker to type) solution after try-and-error: eval(mapply(function(x) {x; function() x}, c("a", "b...

Example: > f <- function(x) { 1 + 2 * log(1 + 3 * x) + rnorm(1, sd = 0.5) } > y <- f(x <- c(1 : 10)); y [1] 4.503841 5.623073 6.336423 6.861151 7.276430 7.620131 7.913338 8.169004 [9...

Ah, now I see... Thanks very much :) On Sat, Oct 01, 2011 at 09:27:34AM -0400, Gabor Grothendieck wrote: > On Sat, Oct 1, 2011 at 5:28 AM, Casper Ti. Vector > <caspervector at gmail.com> wrote: > Its linear given...

For example, prepare like this > df.0 <- data.frame(x = 0, y = 0, note = "1") > df.1 <- subset(df.0, note == "1") > df.2 <- subset(df.0, note == "2") Then a call to > ggplot() + aes(x = x, y = y) + > geom...