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8 results for “from:Geoff Brookshire”

Maximal specification of random effects
Geoff Brookshire · Jun 6, 2013 · r-sig-mixed-models

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Conflicting p-values from pvals.fnc
Geoff Brookshire · Mar 26, 2012 · r-sig-mixed-models

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Estimating p-value for fixed effect which occurs also ininteraction
Geoff Brookshire · May 8, 2012 · r-sig-mixed-models

Here's a similar question from a few months ago, with Ben Bolker's very helpful response: https://stat.ethz.ch/pipermail/r-sig-mixed-models/2011q3/006690.html cheers, geoff On Tue, May 8, 2012 at 7:37 PM...

valid estimates using lme4?
Geoff Brookshire · Oct 28, 2011 · r-sig-mixed-models

This seems to only work if you have a single random effect. You say that Laplace approximation: > may not always work satisfactorily for binary data (for binomial data with > more than one trials it would be a bit better) Since...

Chisq = 0 and p = 1 with nested lmer models
Geoff Brookshire · Sep 28, 2011 · r-sig-mixed-models

Oops! Change fm.F1.2a <- lmer(outcome ~ F2*F3 - F1:F2:F3 + (1 | subject) + (1 | item), data = samp.dat, REML = FALSE) to fm.F1.2a <- lmer(outcome ~ F2*F3 + (1 | subject) + (1 | item), data = samp.dat, REML = FALSE) Sorry for...

Chisq = 0 and p = 1 with nested lmer models
Geoff Brookshire · Sep 15, 2011 · r-sig-mixed-models

Dear all, I'm using lme4 to analyze some reaction time data I've collected, and am running into an odd problem. I'm not certain if it's a bug or a problem with my thinking, but hopefully (and...

Question on significancy of terms
Geoff Brookshire · Sep 12, 2012 · r-sig-mixed-models

Hi there, I asked a similar question about a year ago: https://stat.ethz.ch/pipermail/r-sig-mixed-models/2011q3/006690.html To test for the significance of a, you could either use pvals.mcmc (in the languageR package...

Chisq = 0 and p = 1 with nested lmer models
Geoff Brookshire · Sep 28, 2011 · r-sig-mixed-models

Hi again, After an education-filled delay, this makes perfect sense. I. White pointed out to me that: "it will often make sense to compare a quadratic b0 + b1*x + b2*x^2 with b0 + b1*x, but when would...

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