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This works ok: > cox = coxph(surv ~ bucket*(today + accor + both) + activity, data = data) > fit = survfit(cox, newdata=data[1:100,]) but using strata leads to problems: > cox.s = coxph(surv ~ bucket*(today + accor + both) + strata(activity), > data = data) > fit.s...
Hi! In answer to: -------- I noticed that you were using what might be called an "externally created Surv object". I have a memory that Terry Therneau has criticized that practice. I cannot remember if it was in exactly this situation...
-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 Hi Terry, I attached a small data set to this email. This is what I get (I restricted the formula to avoid NA's): > surv = with(small, Surv(time=absence, event=(censored==FALSE))) > (cox...
Hi, In the following results I interpret exp(coef) as the factor that multiplies the base hazard rate if the corresponding variable is TRUE. For example, when the bucket is ks008 and fidelity <= 3, then the rate, compared to the...
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