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I am trying to predict follow-up time using several survival models, both parametric and semi-parametric. I achieve it for semi parametric models using predict.coxph function in R from survival package using type = "expected" as indicated in help...

You are right. Specifically, I need to predict the mean and median time to failure from a coxph model and several parametric models using new data. Thanks. El lun., 5 nov. 2018 a las 7:11, Therneau, Terry M., Ph...

Thanks Terry but the error persists. See: > library(foreign)> library(survival)> library(VGAM) > mypareto <- list(name='Pareto',+ init= function(x, weights,parms){+ alpha <- length(x)/(sum(log(x)))#this is a MLE for alpha+ c(media <-(alpha*1/(alpha-1...

I don?t know how to write a pareto distribution in that form, I want a pareto function for time because I have a time variable that fits that distribution. For a weibull and lognormal it is very easy because...

Hi, I want to perform a survival analysis using survreg procedure from survival library in R for a pareto distribution for a time variable, so I set the new distribution using the following sintax: library(foreign) library(survival) library(VGAM...

Thanks Terry, I use the following formula for density: [image: f_X(x)= \begin{cases} \frac{\alpha x_\mathrm{m}^\alpha}{x^{\alpha+1}} & x \ge x_\mathrm{m}, \\ 0 & x < x_\mathrm{m}. \end{cases}] Where *x*m is...