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7 results for “from:Jan Hummel”

SAX Parser best practise
Jan Hummel · Sep 22, 2005 · r-help

Thank you Seth and Duncan for your input! > BTW, do you have a schema for the XML document you are working on? Yes, a schema is available here http://psidev.sourceforge.net/ms/xml/mzdata/mzdata.xsd Informations around mzData...

Re-sort list of vectors
Jan Hummel · Aug 15, 2005 · r-help

Hi. Can anyone suggest a simple way to re-sort in R a list of vectors of the following form? input $"1" a b c 1 2 3 $"2" a b c 4 5 6 Output should be something like...

Re-sort list of vectors
Jan Hummel · Aug 16, 2005 · r-help

Dear list members, thank all of you for replying to my question. Finally I came up with 3 working solutions, which I ask you to rank now in terms of used resources, computation speed, "design questions" etc. x <- list("1...

SAX Parser best practise
Jan Hummel · Sep 20, 2005 · r-help

Dear All, I have a question regarding best practise in setting up a XML parser within R. Because I have files with more than 100 MB and I'm only interested in some values I think a SAX-like parser...

Invisible plot using RSvgDevice
Jan Hummel · Jan 10, 2005 · r-help

Dear list members, I have a probably simple question concerning the RSvgDevice. After upgrading from R 1.9.0 to R 2.0.1 the computet svg files looking empty. Each time the RSvgDevice 0.5.3 were used. Scales...

SAX Parser best practise
Jan Hummel · Sep 26, 2005 · r-help

Hi Duncan, thanks again for your comments. > I dug around in the libxml code and the Web to verify that > validation is indeed only possible in libxml when one uses > DOM (i.e. xmlTreeParse()). Using DOM is not an option...

Re-sort list of vectors
Jan Hummel · Aug 15, 2005 · r-help

Thanks a lot! But unfortunately I will not know the dimensions of both lists. And further, the lists may be (partly) disjoint as: x <- list("1"=c(a=1, b=2, c=3), "2"=c(d=4, b=5, e...

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