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Dear Manuel, How about: " column1 <- c("a", "b", "c") column2 <- paste("<= ", c(0.3, 0.5, 0.8)) column3 <- paste("<= ", c(0.5, 0.6, 0.9)) table <- data.frame(column1, column2, column3) table " Watch out not to mix English...
Hi Justine, I modified the feather.plot function creating a feather.plot2 function as coded here under. Using that one instead would produce a feather plot with x and y axis. feather.plot2 <- function (r, theta, xpos, yref = 0, use...
Dear ones, You could also consider the following links: http://cran.r-project.org/web/views/Spatial.html http://www.asdar-book.org/ Best regards, Ya?r Levy Researcher Flemish Government Mobility and Public Works Department Flanders? Hydraulics Berchemlei 115...
Dear Mauricio, I would confirm the use of rgdal::spTransform as appropriate. Also, one could add creating a CRS database as follows: #European Petroleum Survey Group list creation EPSG <- make_EPSG() The geographical ETRS89 CRS is then the following I...
Hi Stacy, To start simple, a loop is written as follows in R: For (i in 1 : x){ } If by ranking, you mean ordering data, than you can use package chron to create time objects that are to my opinion...
Hi Stacey, How we meet again... You could re-project your data by using package sp with function: spTransform The only thing you need is to define the coordinate reference system of your input spatial object when creating it using...
Hi Justine, Which formula are you talking about? I have scripted many hydraulic algorithms and am familiar with your issue although I used other ADCP softwares. The data looks all right to me. Please do specify more in detail what...
Hi everyone, May bei t would be more simple to use function: identify(x = coordinates(coordinate object argument)[, 1], y = coordinates(coordinate object argument)[, 2], labels = Whatever) You would only need to click next to the points of interest to...
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