Search Archives

Is there anyone knowing a function for standard normal cumulative distribution? ?(z=-0.1)=? also ?(z=?)=0.025 -- View this message in context: http://www.nabble.com/function-for-standard-normal-cumulative-distribution-tp20282804p20282804.html Sent from the R help...

Hi there, The data is data<-c(2,6,13,26,19,25,18,11,22,25) I want to count data for these rages: [0~10]: [11~20]: [21-30]: Is anyone can help me? Thank you in advance...

Hi there, I have a data set: a=cbind(5,2,4,7,8,3,4,11,1,20) I want to count # of data, satistfying a[1]<a[2:10]. Anyone helps me solving this case? Thank you in...

I have an error for a simple optimization problem. Is there anyone knowing about this error? lambda1=-9 lambda2=-6 L<-function(a){ s2i2f<-(exp(-lambda1*(250^a)-lambda2*(275^a-250^a)) -exp(-lambda1*(250^a)-lambda2*(300^a...

Data has the first row for variable name and the first column for sample name. I want to take "Log" for all data, but how to compute without the first column for sample name. > log.raw_data=log(raw_data...

Hi, I am thinking about IWLS vs ML estimation. When I use glm() for a 2-parameter distribution (e.g., Weibull), I can otain the MLE of scale parameter given shape parameter through IWLS. Because this scale parameter usually converges...

I have a data set (csv); e.g., ID samp1 samp2 samp3 samp4 G1 23 32 12 87 G2 85 45 49 76 G3 12 46 39 28 G4 73 26 18 13 and read it: data1<-(read.csv("Datafolder...

Hello, Considering 5 points in X-Y plain. Data is a 5*2 matrix (5 rows for samples & 2 columns for X and Y) With a distance from the origin, if a distance < 7, remove the row from the Data...

David, Yes, it is what I want. It is a great help. Thank you, Jin David Winsemius wrote: > > Do you want the count of remaining elements which are strictly > greater than the first element? > > > length(which(a[1] < a[2...

Hello, I have different results from these two softwares for a simple binomial GLM problem. >From Genmod in SAS: LogLikelihood=-4.75, coeff(intercept)=-3.59, coeff(x)=0.95 >From glm in R: LogLikelihood=-0.94, coeff(intercept)=-3...

I am converting exact time data to interval data and generate samples via Bootstraping. I had a quite long code to get the frequency but your help makes it simpler. Thank you.. jholtman wrote: > >> data<-c(2,6,13,26...

Mike, Thank you for your valuable reply. I have read Charnes et al. (1976) and Bradley (1973). However, they just showed the equivalence of IWLS and ML solutions, but didn't mentioned the advantage (or disadvantage) of IWLS comparing with...

I use "while" loop but it produces an errro. I have no idea about this. Error in "[<-"(`*tmp*`, i, value = numeric(0)) : nothing to replace with The problem description is The likelihood includes two parameters to be estimated: lambda (=beta0...

Hello, The likelihood includes two parameters to be estimated: lambda (=beta0+beta1*x) and alpha. The algorithm for the estimation is as following: 1) with alpha=0, estimate lambda (estimate beta0 and beta1 via GLM) 2) with lambda, estimate alpha...