do.call(): no need for quote {was .. Questions about calls..}

"Gabor" == Gabor Grothendieck <ggrothendieck at gmail.com>
    on Mon, 22 Aug 2005 18:55:38 -0400 writes:

..................

    Gabor> Try do.call like this:

    Gabor> ff <- x ~ g*h 
    Gabor> do.call("substitute", list(ff, list(x = as.name("weight"))))

Just a small remark: For all those who -- like me -- have found
it  ``unpleasant'' to have to quote the first argument of do.call():
You don't have to any longer since the NEWS of R 2.1.0 contains

    o	do.call() now takes either a function or a character string as
	its first argument.  The supplied arguments can optionally be
	quoted.

So the above could be 

   do.call(substitute, list(ff, list(x = as.name("weight"))))

--
Martin