troubleshooting data structure to run krippendorff's alpha

Hi all,
Thank you for your responses. You are correct that it is not a matrix. I
used the incorrect term.
I meant I put my data in a spreadsheet with three rows and 24 columns.

Sent from my iPhone

On Jan 28, 2019, at 3:36 AM, Jim Lemon <drjimlemon at gmail.com> wrote:

Hi Halllie,
As Jeff noted, a data frame is not a matrix (it is a variety of list),
so that looks like your problem.

hkdf<-data.frame(sample(3:5,4,TRUE),sample(1:3,4,TRUE),sample(2:4,4,TRUE),

sample(3:5,4,TRUE),sample(1:3,4,TRUE),sample(2:4,4,TRUE))
library(irr)
kripp.alpha(hkdf)
kripp.alpha(as.matrix(hkdf))

Jim

On Mon, Jan 28, 2019 at 6:04 PM Hallie Kamesch <

hallie.kamesch at gmail.com> wrote:

Hi -
I'm trying to run Krippendorff's alpha for data consisting of 4 subjects
rated on 6 events each by three raters.  The ratings are interval ratio
scale data.

I've rearranged my data into a 3 x 24  of ratersXevents. (per this
discussion on CrossValidated: (

https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144
)

).

This is the code I've used:
library(irr)
dat <- read.csv(file.choose(), header = TRUE)
head(dat)
kripp.alpha(dat, method=c("ratio"))
#### error message: Error in sort.list(y) : 'x' must be atomic for
'sort.list'
Have you called 'sort' on a list?
kripp.alpha(dat,"ratio")
#### error message: Error in sort.list(y) : 'x' must be atomic for
'sort.list'
Have you called 'sort' on a list?

I read rhelp on sort, but I'm still confused.  Please help!
Thank you!

PS
I arranged my data in that matrix based upon this comment and response

from

the CrossValidated posting forum (

https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144
),

but my question above was rejected there.

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