odd, even indices of a vector

Hi Carol,

Might be a trivial question but how to identify the odd and even indices of a vector?

x = c(1,z,w,2,6,7)

el of odd indices= 1,w,6
el of even indices= z,2,7

The easiest way is to subset your vector with c(TRUE, FALSE) to keep
only the odd indices:

   > letters[c(TRUE, FALSE)]
   [1] "a" "c" "e" "g" "i" "k" "m" "o" "q" "s" "u" "w" "y"

and with c(FALSE, TRUE) to keep only the even indices:

   > letters[c(FALSE, TRUE)]
   [1] "b" "d" "f" "h" "j" "l" "n" "p" "r" "t" "v" "x" "z"

Note that the above doesn't work properly with vector of length < 2.

A method that works independently of the length of the vector (using
the is.odd and is.even functions from the "identifying odd or even
number" post that you referred to):

   x[is.odd(seq_along(x))]

   x[is.even(seq_along(x))]

Hope this helps,
H.

given the def of odd and even in https://stat.ethz.ch/pipermail/r-help/2010-July/244299.html

should a loop be used?

for (i in 1: length(x))
if (is.odd(i)) print (i)


Carol

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