troubleshooting data structure to run krippendorff's alpha
Hi all, Thank you for your responses. You are correct that it is not a matrix. I used the incorrect term. I meant I put my data in a spreadsheet with three rows and 24 columns. Sent from my iPhone
On Jan 28, 2019, at 3:36 AM, Jim Lemon <drjimlemon at gmail.com> wrote: Hi Halllie, As Jeff noted, a data frame is not a matrix (it is a variety of list), so that looks like your problem. hkdf<-data.frame(sample(3:5,4,TRUE),sample(1:3,4,TRUE),sample(2:4,4,TRUE), sample(3:5,4,TRUE),sample(1:3,4,TRUE),sample(2:4,4,TRUE)) library(irr) kripp.alpha(hkdf) kripp.alpha(as.matrix(hkdf)) Jim
On Mon, Jan 28, 2019 at 6:04 PM Hallie Kamesch <hallie.kamesch at gmail.com> wrote: Hi - I'm trying to run Krippendorff's alpha for data consisting of 4 subjects rated on 6 events each by three raters. The ratings are interval ratio scale data. I've rearranged my data into a 3 x 24 of ratersXevents. (per this discussion on CrossValidated: ( https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144) ). This is the code I've used: library(irr) dat <- read.csv(file.choose(), header = TRUE) head(dat) kripp.alpha(dat, method=c("ratio")) #### error message: Error in sort.list(y) : 'x' must be atomic for 'sort.list' Have you called 'sort' on a list? kripp.alpha(dat,"ratio") #### error message: Error in sort.list(y) : 'x' must be atomic for 'sort.list' Have you called 'sort' on a list? I read rhelp on sort, but I'm still confused. Please help! Thank you! PS I arranged my data in that matrix based upon this comment and response from the CrossValidated posting forum ( https://stats.stackexchange.com/questions/255164/inter-rater-reliability-for-binomial-repeated-ratings-from-two-or-more-raters/256144#256144), but my question above was rejected there. [[alternative HTML version deleted]]
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