subset every 5th row
Hi Veepsirtt, May be this helps: dat1 <- structure(list(V2 = c(11109.75, 11135.15, 11105.85, 11099.75, 11055.55, 11063.45, 11045.65, 11065, 11061.2, 11070.25, 11069.3, 11076, 11081.85, 11086.4, 11086.7, 11065.6, 11071.25, 11073.15, 11077.8, 11067.7, 11061.1, 11065.9, 11069.1, 11063.3, 11070.45, 11074.4, 11069.4, 11063.65, 11067.05, 11070.1, 11074, 11069.6, 11072.65, 11073.7, 11061.35, 11064.2, 11066.85, 11078.15, 11079.65, 11079.5, 11075.9, 11066.95, 11072.55, 11068.85, 11073.5, 11067.6, 11055.3, 11053.3, 11052.65, 11047.6, 11045.25, 11028.9, 11036.15, 11034.3, 11044.05, 11030.65, 11036.6, 11039.75, 11035.35, 11019.05 )), .Names = "V2", class = "data.frame", row.names = c(NA, 60L )) dat1[seq(5,nrow(dat1),by=5),,drop=FALSE] #or dat1[((seq(nrow(dat1))-1)%%5+1)==5,,drop=FALSE] A.K.
On Sunday, January 19, 2014 9:40 AM, "veepsirtt at gmail.com" <veepsirtt at gmail.com> wrote:
Hi A.K sir 1,11109.75 2,11135.15 3,11105.85 4,11099.75 5,11055.55 6,11063.45 7,11045.65 8,11065 9,11061.2 10,11070.25 11,11069.3 12,11076 13,11081.85 14,11086.4 15,11086.7 16,11065.6 17,11071.25 18,11073.15 19,11077.8 20,11067.7 21,11061.1 22,11065.9 23,11069.1 24,11063.3 25,11070.45 26,11074.4 27,11069.4 28,11063.65 29,11067.05 30,11070.1 31,11074 32,11069.6 33,11072.65 34,11073.7 35,11061.35 36,11064.2 37,11066.85 38,11078.15 39,11079.65 40,11079.5 41,11075.9 42,11066.95 43,11072.55 44,11068.85 45,11073.5 46,11067.6 47,11055.3 48,11053.3 49,11052.65 50,11047.6 51,11045.25 52,11028.9 53,11036.15 54,11034.3 55,11044.05 56,11030.65 57,11036.6 58,11039.75 59,11035.35 60,11019.05 thanks veepsirtt _____________________________________ Sent from http://r.789695.n4.nabble.com