Integration subroutine?
The function need to be vectorized. Try:
fr2.new <- function(x) ifelse(x < 1, x * x, 1) integrate(fr2.new, -1, 2)
1.666667 with absolute error < 3.4e-05 Andy From: Lynette Sun
Hi all,
Why
fr2<-function(x)
{ if(x<1){x*x}else{1}
}
integrate(fr2,-1,2)
gives the following wrong answer:
3 with absolute error < 3.3e-14
Warning message:
the condition has length > 1 and only the first element will
be used in: if (x < 1) {
while
fr<-function(x){as.numeric(x<1)*(x^2-1)+1}
integrate(fr,-1,2)
works?
1.666667 with absolute error < 3.4e-05
Thanks.
Lynette Sun
Department of Statistics
[[alternative HTML version deleted]]
______________________________________________ R-help at stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html