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R-sig-mixed-models Digest, Vol 77, Issue 11

3 messages · Volker Dellwo, Jake Westfall, Douglas Bates

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Hi Jake,

thanks a million for your answer!
> Obviously this kind of test doesn't make sense.

Yes, I totally agree. But then I did this:
	speaker <- factor(bt.data$speaker);
	sentence <- factor(bt.data$sentence);
	tempo <- factor(bt.data$tempo);
 From what I read it seems to me that the three variables should then be 
treated as factor objects; am I right or wrong here?

With is.factor(speaker), for example, I receive the response "TRUE"

Best wishes,
Volker